Verification that the generic case has one solution ---------------------------------------------------------------- (C1) eqns:[ (2) * U1 + ( - X2 - X3), (2) * V1 + ( - Y3), (2) * U2 + ( - X3), (2) * V2 + ( - Y3), (2) * U3 + ( - X2), (2) * V3, ( - 3 * X2 * Y3) * Y + (X2 * Y3^2), ( - 3 * X2 * Y3^2) * X + (X2^2 * Y3^2 + X2 * X3 * Y3^2) ]; (D1) [- X3 - X2 + 2 U1, 2 V1 - Y3, 2 U2 - X3, 2 V2 - Y3, 2 U3 - X2, 2 V3, 2 2 2 2 2 X2 Y3 - 3 X2 Y Y3, X2 X3 Y3 + X2 Y3 - 3 X X2 Y3 ] (C2) solve(%,[x,y,u1,v1,u2,v2,u3,v3]); X3 + X2 Y3 X3 + X2 Y3 X3 Y3 X2 (D2) [[X = -------, Y = --, U1 = -------, V1 = --, U2 = --, V2 = --, U3 = --, 3 3 2 2 2 2 2 ---------------------------------------------------------------- >(load "midpoints") Loading midpoints.lisp Condition: Green list: [ ] Red list: [ X2 * Y3^2 ] Basis: [ (2) * U1 + ( - X2 - X3), (2) * V1 + ( - Y3), (2) * U2 + ( - X3), (2) * V2 + ( - Y3), (2) * U3 + ( - X2), (2) * V3, ( - 3 * X2 * Y3) * Y + (X2 * Y3^2), ( - 3 * X2 * Y3^2) * X + (X2^2 * Y3^2 + X2 * X3 * Y3^2) ] Condition: Green list: [ X2 ] Red list: [ Y3 ] Basis: [ (2) * U1 + ( - X3), (2) * V1 + ( - Y3), (2) * U2 + ( - X3), (2) * V2 + ( - Y3), (2) * U3, (2) * V3, ( - Y3) * X + (X3) * Y ] Condition: Green list: [ Y3 ] Red list: [ X2 + X3 ] Basis: [ (2) * U1 + ( - X2 - X3), (2) * V1, (2) * U2 + ( - X3), (2) * V2, (2) * U3 + ( - X2), (2) * V3, (X2 + X3) * Y ] Condition: Green list: [ Y3, X2 + X3 ] Red list: [ X3 ] Basis: [ (2) * U1, (2) * V1, (2) * U2 + ( - X3), (2) * V2, (2) * U3 + (X3), (2) * V3, (3 * X3) * Y ] Condition: Green list: [ X2, Y3, X3 ] Red list: [ ] Basis: [ (2) * U1, (2) * V1, (2) * U2, (2) * V2, (2) * U3, (2) * V3 ] Finished loading midpoints.lisp T